SecondaryCurrent = 139.1 Amperes. Now calculate for the rating of transformer according to. P = V x I (Primary voltage x primary current) P = 11000V x 5.25A = 57,750 VA = 57.75kVA. Or P = V x I (Secondary voltages x Secondary Current) P= 415V x 139.1A = 57,726 VA = 57.72kVA.
CableSize Calculation of 125 Kw LT Motor. Load Current = P / (1.732 x V x Pf x Eff) —> (P = √3 x Vx I CosΦ = for three phase circuits) This is the full load current cable needs to cater in Ideal condition. But in practical situation, there areElectricMotor, Three Phase 5.5kw 7.5HP. 4 Pole = 1400rpm. Amps at 400v - 10.81. Frame Size - MS133S-4. Rugged and Reliable. Lightweight aluminium Construction. Suitable for wet and dusty applications. 50/60hz rated. Inverter drive rated.01 kW: 0.1359621617 horsepower (metric) 1 kW: 1.3596216173 horsepower (metric) 2 kW: 2.7192432346 horsepower (metric) 3 kW: 4.0788648519 horsepower (metric) 5 kW: 6.7981080865 horsepower (metric) 10 kW: 13.596216173 horsepower (metric) 20 kW: 27.1924323461 horsepower (metric) 50 kW: 67.9810808652 horsepower (metric) 100
Theformula to convert kVA to amps in a three-phase circuit looks like this: I (A) = S (kVA) × 1,000 / √3 × V L-L(V) For a balanced load where the current is the same on all phases, the current I in amps is equal to 1,000 times the apparent power S in kVA divided by the square root of 3 (1.732) times the line to line voltage V .
Howmany amps does a 5.5 kw 380 v three phase motor draw? Updated: 10/3/2023 Wiki User ∙ 9y ago Study now See answers (2) Best Answer Copy Current
Usingthe formula: Amps (I) = (5 HP × 746) / (sqrt (3) × 230 V) Amps (I) ≈ 14.08 A So, a 5 HP 3-phase motor at 230 volts draws approximately 14.08 amps. What.